2a^2+14a-240=0

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Solution for 2a^2+14a-240=0 equation:



2a^2+14a-240=0
a = 2; b = 14; c = -240;
Δ = b2-4ac
Δ = 142-4·2·(-240)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-46}{2*2}=\frac{-60}{4} =-15 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+46}{2*2}=\frac{32}{4} =8 $

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